Question

You have three resistors of values 2 Ω, 3 Ω and 5 Ω. How will you join them so that the total resistance is more than 7Ω? Draw a diagram for the arrangement and calculate the equivalent resistance. ​

Answer 1

Answer:

We will join the resistors in series combination so that we will get total resistance equal to 10 I.e, more than 7

Explanation:

in series combination we directly add the resistance of the resistor

2+3+5 = 10

Answer 2

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${\tt{\red{\underline{\underline{\huge{Answer:}}}}}}$

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$\sf\green{ If \:we \:connect\: the\: resistors \:in \:series\: then\: the }$

$\sf\green{equivalent\: resistance\: of \: the\: circuit \:increases. }$

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Thus, if 2 Ω, 3Ω, 5Ω, resistors are connected in series,

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Then the equivalent resistance

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{Req \:2Ω +\: 3Ω +\: 5Ω=\: 10Ω }} }\\ \\\end{gathered}\end{gathered}$

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Thus, by connecting these resistors in series we can obtain the equivalent resistance greater than 7Ω

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$\sf\color{blue}{Diagram\: in \: attachment}$

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${\huge{\underline{\small{\mathbb{\blue{HOPE\:HELP\:U\:BUDDY :)}}}}}}$