CBSE BOARD XII, asked by rockingmohit432, 6 months ago

You have to calculate the total surface area & curved surface area of a cone if it's radius is 14m & slant height is 28 m.​

Answers

Answered by Anonymous
51

\large{\red{\bold{\underline{Given:}}}}

 \sf \: (i) \: Slant \: height \: of \: the \: cone (l) = 28m \\  \\  \sf \: (ii) \: Radius \: of \: its \: base(r) = 14m

\large{\green{\bold{\underline{To \: Find:}}}}

 \sf \: (i) \: Total \: surface \: area \: of \: cone \\  \\  \sf \: (ii) \: Curved \: surface \: area \: of \: cone

\large{\blue{\bold{\underline{Formula \: Used:}}}}

 \sf \: Total  \: surface \:  area = \pi rl + \pi {r}^{2} \\  \\  \sf \: Curved \:  surface \:  area = \pi rl

\large{\red{\bold{\underline{Solution:}}}}

 \sf \: Let's \: consider \: total \: surface \: area \: as \: T.S.A. \\ \sf \: And \: curved \: surface \: area \: as \: C.S.A.

\large{\pink{\bold{\underline{Then:}}}}

 \sf \:  \longrightarrow \: T.S.A = \pi r(r + l) \\  \\  \longrightarrow \: \sf \: T.S.A =  \frac{22}{7}  \times 14(14 + 28) \\  \\  \longrightarrow \: \sf \: T.S.A =  \frac{22}{7}  \times 14(42) \\  \\  \longrightarrow \: \sf \: T.S.A =  \frac{22}{\cancel7}  \times \cancel14(42) \\  \\ \longrightarrow \: \sf \:T.S.A = 22 \times 2 \times 42 \\  \\ \longrightarrow \: \sf \:T.S.A = 1848 \:  {m}^{2}

\large{\green{\bold{\underline{And:}}}}

 \sf  \longrightarrow \: \sf \: C.S.A = \pi rl \\  \\ \longrightarrow \: \sf \: C.S.A =  \frac{22}{7} \times 14 \times 28 \\  \\ \longrightarrow \: \sf \: C.S.A =  \frac{22}{\cancel7} \times \cancel14 \times 28 \\  \\ \longrightarrow \: \sf \: C.S.A = 22 \times 2 \times 28 \\  \\ \longrightarrow \: \sf \: C.S.A = 1232 \:  {m}^{2}

\large{\red{\bold{\underline{Therefore:}}}}

 \sf \: Total \: surface \: area \: of \: cone \: is \: 1848 {m}^{2} \: and \\ \sf \: curved \: surface \: area \: of \: cone \: is \: 1232 {m}^{2}.


mddilshad11ab: perfect:)
Answered by Anonymous
62

 \sf{ \purple{\Large{Given:}}}

◎ Radius of its circular base i.e., r = 14 m

◎ Slant height of a cone i.e., l = 28 m

 \sf{ \purple{\Large{To \: Find}}}

๑ Total surface area of a cone

๑ Curved surface area of a cone

 \sf{ \purple{\Large{Solution:}}}

Now by using formula we will find both Total surface area and Curved surface area of a cone.

Total Surface Area = Base Area + Curved Surface Area.

T.S.A = πr² + πrl

Formula for total surface area of a cone

 \underline{ \boxed{ \sf{T.S.A =  \pi r(r + l)}}}

Substituting the values in the formula, we have:

 \sf{ T.S.A=  \dfrac{22}{7}  \times 14(14 + 28)}

 \sf{T.S.A =  \dfrac{22}{7}  \times 14(42)}

 \sf{T.S.A =  \dfrac{22}{ \cancel 7}  \times \cancel {14} \times 42}

 \sf{T.S.A =  22  \times 2 \times 42}

 \sf{T.S.A = 1848 \:  {m}^{2} }

Total surface area of cone = { \green{\underline{ \boxed{ \sf{1848 \:  {m}^{2} }}}}}

Now,

Formula for calculating curved surface area of cone

\underline{ \boxed{ \sf{Curved \: Surface \: Area = \pi rl }}}

On Substituting the values in the formula, we have:

 \sf{C.S.A =  \dfrac{22}{7}  \times 14 \times 28}

  \sf{C.S.A =  \dfrac{22}{ \cancel7}  \times  \cancel  4} \times 28

 \sf{C.S.A = 22 \times 2 \times 28}

 \sf{C.S.A = 1232 \:  {m}^{2} }

Curved surface area of cone =  \green{\underline{ \boxed{ \sf{1232 \:  {m}^{2} }}}}

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mddilshad11ab: Awesome:)
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