Question

You have two wires of same length and same thickness.one is made of material A(resistivity = 1.6*10^-8) and other is made of material D(resistivity = 96*10^-8).If resistance of wire made of A is 2 ohm.what is the resistance of other wire?

Answer 1

I hope this is your answer

Answer 2

The resistance of other wire is 120 ohms.

Explanation:

Resistivity of material A, $\rho_1=1.6\times 10^{-8}\ \Omega-m$

Resistivity of material B, $\rho_2=96\times 10^{-8}\ \Omega-m$

The resistance of wire A, $R_1=2\ \Omega$

We need to find the resistance of wire B. It can be calculated using formula of resistance in terms of resistivity as :

$R=\rho\dfrac{l}{A}$

Since, two wires of same length and same thickness. So,

For two wires,

$\dfrac{R_1}{R_2}=\dfrac{\rho_1}{\rho_2}$

$\dfrac{R_1}{R_2}=\dfrac{\rho_1}{\rho_2}$

$R_2=\dfrac{R_1\rho_2}{\rho_1}$

$R_2=\dfrac{2\times 96\times 10^{-8}}{1.6\times 10^{-8}}$

$R_2=120\ \Omega$

So, the resistance of other wire is 120 ohms. Hence, this is the required solution.

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