Question

You place a box weighing 333.2 N on an inclined plane that makes a 42.9 angle with the horizontal compute the component of the gravitational force acting down the inclined plane. Answer in units of N.

Answer 1

Answer: 226.8 N

Explanation:

On an inclined plane, component of the weight i.e. gravitational force acting in opposite direction to normal force is $mgcos\theta$ and the component acting down the inclined plane is $mgsin\theta.$

It is given that the weight of the block is, mg= 333.2 N

The angle made with the inclined plane is 42.9°

$\Rightarrow mgsin\theta = 333.2 N sin 42.9^o =226.8 N$

Hence, the component of the gravitational force acting down the inclined plane is 226.8 N.