you roll a die write the probability of rolling a prime number as a decimel
Answers
Step-by-step explanation:
First, the die must be a die without tricks !… A sound die!…
Second, the probability of all events that can happen is = 1.0 or 100%
and third, the prime numbers of 1 to 100 are = 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97
A die has six (6) side numbered: 1, 2, 3, 4, 5, 6. Observing these number, we noted that there are three prime number. They are 2, 3 and 5. Ok?…
Understanding it, it is easy to solve the problem!…
Now, to calculate the probability, please count or sum the sides of die and forget the numbers (the number in this case are not important for calculation of this kind of probability!…)
How many sides did you count or sum?… You must have counted or summed six (6) sides!… Ok?…
Now, count the sides that have prime numbers, you must have counted three (because three sides has prime number)… Ok?…
Then, we divide the number of sides that have prime number 2, 3, 5 = 3 sides by the total number of sides = 6 sides
= 3/6 Ok?…
Now, we can simplify this result, dividing simultaneously the numerator (3) and denominator (6) by 3 (because 3 in this case is the number that divide them exactly) … OK?!…
The result that we got is = 1/2 … Ok?…
Now, we transform the fraction (1/2) in a proportion (decimal) doing the division (1 divided 2)
the result is = 0.5, Ok?…
Now, we transform the proportion (decimal) result in a percentage (%), multiplying it by 100%
0.5 * 100% = 50%
Note: we can obtain the same percentage result, multiplying the fraction by 100%
1/2 * 100% = 100%/2 = 50%
CONCLUSION: The probability to obtain a prime number in a die is = 1/2 = 0.5 = 50%
I hope to have helped!
GOD BLESS YOU!…
there will be the probability of 1/6 , 2/6,3/6,4/6,5/6,6/6