You roll two fair dice. Calculate each probability.
a. P(doubles) b. P(sum of 7) c. P(sum of 11)
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Answer:
Total Outcomes =36
Number of doubles =(1,1) , (2,2),(3,3),(4,4),(5,5),(6,6)
possible outcomes in this case =6
1) P( doubles) =(6/36)=(1/6)
next we can get sum of 7 when the dices will show
(1,6),(6,1),(2,5),(5,2),(3,4),(4,3)
possible outcomes in this case =6
2)P(sum of 7) = (6/36)=(1/6)
we can get sum of 11 when the dice will show (5,6),(6,5)
possible outcomes in this case = 2
P(Sum of 11) = (2/36) =(1/18)
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