Question

you walk 5 km to the South and then 3 km 30 degree West bof south what is final displacement.​

Answer 1

Answer:

the displacement of the man is 7.74 km at 11.2 degree West of South

Explanation:

Here we assume East as positive X direction and North as positive Y direction

So here it move towards South by 5 km and then 3 km 30 degree West of South

so we have

$d_1 = -5\hat j$

$d_2 = -3sin30\hat i - 3cos30\hat j$

so we have

$d = d_1 + d_2$

$d = (-1.5 \hat i - 1.5\sqrt3\hat j) - 5\hat j$

$d = -1.5 \hat i - 7.6 \hat j$

so here we can say that the displacement is

$d = \sqrt{(-1.5)^2 + (-7.6)^2}$

$d = 7.74 m$

direction is given as

$\theta = tan^{-1}(\frac{1.5}{7.6})$

$\theta = 11.2 degree$

So the displacement of the man is 7.74 km at 11.2 degree West of South

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Topic : Displacement

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