Physics, asked by koushik86, 11 months ago

youngs module of material of wire is 12.6×10^11 dyne/cm^2.Its value in MKS system is

Answers

Answered by kunisettisunanda2000
0

Answer:

12.6x10^10.

Explanation:

young's modulus (Y) units are Nm^-2.

So dimensional formula of young's modulus is = ML^(-1) T^(-2).

here using dimension formula powers of young's modulus.

1 dyne/cm^2 = (1gm)(1cm)^-1 (1sec)^-2.

1N/m^2 = (1kg)(1m)^-1(1sec)^-2.

12.6x10^11 dyne/cm^2 = (1gm)x(1cm)^-1 x(1sec)^-2.

           1N/m^2                    (1kg)x(1m)^-1x(1sec)^-2.

dyne/cm^2 = (1gm)  x (1cm)^-1  x (1sec)^-2.         .

     1N/m^2        (1000g)   (100cm)^-1  (1sec)^-2.

dyne/cm^2 = (1)  x    (1)^-1       .

 1N/m^2           (1000) x(100)^-1

dyne/cm^2  =  100

1N/m^2             1000

dyne/cm^2  =   1

  1N/m^2            10

         1      dyne/cm^2       =             1      N/m^2

                                                         10        

12x10^11    dyne/cm^2         =              ?    

  • 12x10^10 N/m^2

     

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