Question

Your body is executing SHM with amplitude a and angular frequency Omega the root mean square speed of the body for one complete oscillation will be position of the particle at equal to zero is mean position

Answer 1

We know for a SHM velocity is

v=ω[√(A²-x²)]

and max speed is vₘ=ωA

by question speed is Aω/2

∴A²ω²/4 =A²ω²-ω²x²

solving we get x²=3A²/4

so its displacement is ±√3A/2 from mean position