Question

yr meko ye ni samazhra.....
samzhado koe...
$- 3y = 4 - 2x \\ - 3y = 4 - 2( - 1) \\ - 3y = 4 + 2 \\ y = \frac{6}{3} \\ y = 2$
now here concentrate on -3y. when it goes to the right side the negative sign is changed into positive. but my maths calculator is not showing that. see in attachment n tell which one is right one.​

Answer 1

-3y = 4 - 2x

⇒ -3y = 4 - (2*x)

⇒ -3y = 4 - (2*-1)

⇒ -3y = 4 - (-2)

⇒ -3y = 4 + 2

⇒ -3y = 6

⇒ -y = 6/3

⇒ -y = 2

⇒ y = -2

in your own calculation, you wrote:

-3y = 4 + 2

Here (-3y) is in LHS.

In the next step, you wrote:

y = 6/3

So, in this step, you made a mistake.

You removed the (-) sign from 'y', whereas 'y' is still there in the LHS.

So, your calculator is correct.

hope you understand..

Answer 2

ANSWER IN ATTACHMENT FILE