Question

Yusuf puts 13 red balls, 8 green balls and 9 yellow into a bag. what is the chance of him selecting a green ball from the bag?

Answer 1

$\bold{\underline{\underline{\huge{\sf{AnsWer:}}}}}$

Chance of Yusuf selecting a green ball from the bag = 0.26

$\bold{\underline{\underline{\large{\sf{StEp\:by\:stEp\:explanation:}}}}}$

GiVeN :

• Yusuf puts 13 red balls, 8 green balls and 9 yellow balls into a bag.

To FiNd :

• The chance (probability) of Yusuf selecting a green ball from the bag.

SoLuTiOn :

First we will calculate the total number of balls in the bag.

We have 13 red balls,

$\sf{R_1,R_2,R_3,R_4,R_5,R_6,R_7,R_8,R_9,R_{10},R_{11},R_{12},R_{13}}$

Next we have 8 green balls,

$\sf{G_1,G_2,G_3,G_4,G_5,G_6,G_7,G_8}$

And then there are 9 yellow balls,

$\sf{Y_1,Y_2,Y_3,Y_4,Y_5,Y_6,Y_7,Y_8,Y_9}$

Let S be the sample space.

$\sf{\therefore{The\:sample\:space\:}}$

$\sf{S\:=\:R_1,R_2,R_3,R_4,R_5,R_6,R_7,R_8,R_9,R_{10},R_{11},R_{12},R_{13},G_1,G_2,G_3,G_4,G_5,G_6,G_7,G_8,Y_1,Y_2,Y_3,Y_4,Y_5,Y_6,Y_7,Y_8,Y_9}$

$\sf{n(S)\:=\:30}$

Now out of these 30 balls (altogether) we have 8 green balls in the bag too.

Let A be the event that Yusuf selects a green ball.

$\sf{A\:=\:G_1,G_2,G_3,G_4,G_5,G_6,G_7,G_8}$

$\sf{\therefore{n(A)\:=\:8}}$

Probability of event A,

$\sf{P(A)\:=\:{\dfrac{n(A)}{n(S)}}}$

$\sf{P(A)\:=\:{\dfrac{8}{30}}}$

$\sf{P(A)\:=\:0.26}$

$\sf{\therefore{Probability\:of\:Yusuf\:drawing\:a\:green\:ball\:from\:the\:bag\:=\:0.26}}$

Thank you,Brainly! :D