z+1÷3=z-1÷2
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Answer:
z+1÷3 = z-1÷2
z/3 + 1/3 = z/2 - 1/2
z/3-z/2 = -1/3-1/2
2z-3z/6 = -2-3/6
z/6 = -5/6
z = -5/6× 6
z = -5
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