Question

Z 굵 1. Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.​

Answer 1

answer:

22.5 : 30

Explanation:

area of 1st triangle = 1/2×( base× height)

= 22.5

area of 2nd triangle =30

hope it helps !!!

Answer 2

Answer:

Heya !!

Here's your answer.. ⬇⬇

♦ Given :- Let The triangle be ∆ABC and ∆PQR.

In ∆ABC,

Base of ∆ABC is BC = 9cm

Altitude of ∆ABC is AE = 5cm

In ∆PQR,

Base is QR = 10cm

Altitude is PM = 6cm

♦ To Find :- Ratio of Area of ∆ABC and ∆PQR

♦ Solution :-

\begin{gathered} = \frac{area \: \: of \: \: abc}{area \: \: of \: \: pqr} \\ \\ = \frac{ \frac{1}{2} \times ae \times bc }{ \frac{1}{2} \times pm \times qr } \\ \\ = \frac{ \frac{1}{2} \times 5 \times 9 }{ \frac{1}{2} \times 6 \times 10} \\ \\ = \frac{3}{4} \\ \\ \end{gathered}=areaofpqrareaofabc=21×pm×qr21×ae×bc=21×6×1021×5×9=43

Hence, Ratio of Area of ∆ABC to ∆PQR is 3:4

Hope it helps..

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