z=-1-i√3 covert to polar form
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Z=1+i
3
=2(
2
1
+i
2
3
)...........(1)
Let Polar form of Given Equation be Z=rcosθ+ir sinθ...............(2)
Comparing (1) and (2)
we can write,
rcosθ=2∗
2
1
=2cos60
o
rsinθ=2∗
2
1
=2sin60
o
∴Z=2(cos60
o
+isin60
o
)
Step-by-step explanation:
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