Question

z=1+i then find theta​

Answer 1

Step-by-step explanation:

We have,

$z = 1 + i$

$= \sqrt{2} ( \frac{1}{ \sqrt{2} } + \frac{1}{ \sqrt{2} } i)$

$= \sqrt{2} ( \cos( \frac{\pi}{4} ) + i \sin( \frac{\pi}{4} ) )$

Hence, arg(z) = $\frac{\pi}{4}$

Answer 2

Answer:

45° = π/4

Step-by-step explanation:

z = 1 + i

tanθ = |1/1|

tanθ = 1

θ = 45° = π/4