Question

z=2-i√3 then z^4-4z^2+8z35​

Answer 1

The equation would then look like this: t2+4t+ 6 ... Now replace t with z2 you get that z=±√− 2−√2i and z=±√2+√2i. Solving that, you should have 4 different imaginary answers for z.

Missing: 8z35 ‎| ‎Must include: ‎8z35