Z = 2 then arg(Z)
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Answered by
2
Answer:
0
Step-by-step explanation:
A] Let z
1
=cosθ
1
+isinθ
1
z
2
=cosθ
2
+isinθ
2
z
1
+z
2
=(cosθ
1
+cosθ
2
)+i(sinθ
1
+sinθ
2
)
As ∣z
1
+z
2
∣=∣z
1
∣+∣z
2
∣
=
(cosθ
1
+cosθ
2
)
2
+(sinθ
1
+sinθ
2
)
2
=1+1
=2(1+cos(θ
1
−θ
2
))=4 [squaring]
=cos(θ
1
−θ
2
)=1
=θ
1
−θ
2
=0 [as cos0
∘
=1]
=Argz
1
−Argz
2
=0
Answered by
1
arg z1- arg z2
hope it's help you
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