Z/2 + Z/3 + Z/6 = 8 explain briefly
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we have to solve equation, z/2 + z/3 - z/6 = 8
Taking LCM of denominators of (z/2), (z/3) and (z/6).
or, LCM of {2, 3, 6} = 6
now write each fraction in such a way that denominator of it will be 6.
i.e., z/2 = (3 × z)/(3 × 2) = 3z/6
z/3 = (2 × z)/(2 × 3) = 2z/6
z/6 = (1 × z)/(1 × 6) = z/6
now, z/2 + z/3 - z/6 is converted into (3z/6 + 2z/6 - z/6)
so, 3z/6 + 2z/6 - z/6 = 8
or, (3z + 2z - z)/6 = 8
or, (5z - z)/6 = 8
or, 4z/6 = 8
or, z = 12
hence, value of z =12
HOPE you understand and like
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