Question

z/2+z/3-z/6=8 solve the equation

Answer 1

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here is your answer....


z/2+z/3–z/6=8

z = 12

Answer 2

$\frac{z}{2} + \frac{z}{3} - \frac{z}{6} = 8 \\ = > \frac{3z + 2z - z}{6} = \frac{48}{6} \\ = > 5z - z = 48 \\ = > 4z = 48 \\ = > z = \frac{48}{4} \\ = > z = 12$


$\textbf{Answer :}$ 12

In the $\textbf{first step}$ you may had a confusion.

Here, we have to make the dinominators equal of both LHS and RHS.

Then we can directly cancel 6 as dinominators from LHS and RHS.

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$\textbf{Hope it helps you!}$

$\textbf{Have a great day ahead!}$
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