Question

z+8/z= 6 find the roots of the quadratic equation by factorisation​

Answer 1

Answer:hope it helps (purple you)

Answer 2

Answer:

$\frac{z {}^{2} + 8}{z} = 6 \: \:by \: lcm$

$z( \frac{ {z}^{2} + 8}{z } )= 6z \: \\ \: \: \: \: \: \: multiplied \: by \: z \: to \: remove \: denominator$

$on \: cancelling \: we \: get$

$z {}^{2} - 6z + 8 = 0$

$z {}^{2} + ( - 4 - 2)z + 8 = 0$

$z {}^{2} - 4z - 2z + 8 = 0$

$z(z - 4) - 2(z - 4) = 0$

$(z - 4)(z - 2)$

$either \: z - 4 = 0 \: \: \: \\ z = 4$

$or \: z - 2 = 0 \\ z = 2$