Math, asked by nitin98lko, 4 months ago

Z is a three digit numbers such that all its digits are consecutive whole number(no zeros) with no repetition for example 867 and 765 are valid but 102 is not .how many of the Z are divisible by 12?

Answers

Answered by amitnrw
3

Given : Z is a three digit numbers such that all its digits are consecutive whole number(no zeros) with no repetition for example 867 and 765 are valid but 102 is not .

To Find :  how many of the Z are divisible by 12

Solution:

three consecutive number

N -1 , N , N + 1  = 3N  Divisible by 3

Hence to be divisible by 12 it must be divisible by 4 also

Number is divisible by 4 if last  two digits are divisible by 4

04 , 08 , 12 , 16 , 20 , 24 , 28 , 32 , 36 , 40 , 44 , 48 , 52 , 56  , 60 , 64 , 68 , 72 , 76 , 80 , 84 , 88 , 92 , 96

0 not used m repetition of digits not allowed

and maximum difference between digits = 2    N +1 - (N - 1) = 2

Hence only number satisfying these

12 , 24 ,  32 , 56 , 64 , 68 , 76

312

324

456

756

564

768

576

876

There are 8 such possible numbers

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