Question

Z varies directly as the square of w, and z = 14 when w = 4. Find z when w = 8?

Answer 1

$z \: > > \: {w}^{2} \\ \\ \frac{ {z}^{.} }{ {z}^{..} } = ( { \frac{{w}^{.} }{ {w}^{..} } })^{2} \\ \\ given \\ \\ {z}^{.} = 14 \\ \\ {w}^{.} = 4 \\ \\ {w}^{..} = 8 \\ \\ {z}^{..} = 14 \times ( { \frac{8}{4} })^{2} \\ \\ {z}^{..} = 14 \times 4 = 56 \\ \\ \\ {z}^{..} = 56$

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