Question

Z1= 2+3i Z2=4-3i then z1 ÷z2 equals to

Answer 1

Answer:

The answer is $\dfrac{-1+18i}{25}$

Step-by-step explanation:

Given

  $z_1=2+3i, z_2=4-3i$

Therefore

 $\dfrac{z_1}{z_2}=\dfrac{2+3i}{4-3i}$

      $=\dfrac{2+3i}{4-3i}\times \dfrac{4+3i}{4+3i}\\\\=\dfrac{8+12i+6i+9i^2}{4^2-(3i)^2}$

      $=\dfrac{8+18i+9(-1)}{16-9(-1)}\\\\\\=\dfrac{-1+18i}{25}$$\boxed{\because i^2=-1}$