Question

z2 + 160 - 26z factorization​

Answer 1

${z}^{2} + 160 - 26z \\ {z}^{2} - 26z + 160 \\ {z}^{2} - 10z - 16z + 160 \\ z(z - 10) - 16(z - 10) \\ (z - 16)(z - 10)$

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