ZA man weighing 50 kg f supports a body of 25 kg f
on his head. What is the work done when he moves
a distance of 20 m up an incline of 1 in 10 ? Take
8 = 9.8 ms
(Ans. 1470 J)
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and incline of one in 10 means that in moving 20 m he reached a height of H= 2 m.
total weight of man and block = 75kg
thus work done is: mgH
75*9.8*2 = 1470J
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