Zaheer travels 1 km due east; then 5km due south, then 2km due east finally 9km due north. How far is he from the starting point
Answers
Step-by-step explanation:
Suppose Zaheer starts travelling from origin.
He travels 1 km East, then 5 km South, then 2 km East and finally 9 km North.
So, he makes a right angle triangle ABC from origin with base BC =4 km and side AB =3 km.
∴ by Pythagoras Theorem,
AB
2
+ BC
2
= AC
2
.
3
2
+4
2
= AC
2
∴ AC=5 km.
Hence, Zaheer is 5 km far from the starting point.
Answer:
5 KM
Step-by-step explanation:
Let Zaheer start from the origin.
As mentioned, he travels 1 km to the East. Then he travels 5km to the south.
Then he travels 2km to the East and finally 9km to the North.
So now, when you draw the diagram you will see a right-angled triangle.
The base of this triangle will be 1km + 2km = 3km
And its height will be 4km.
Let the height be AB and base be BC and hypotenuse be AC.
So using the Pythagoras theorem,
AB² + BC² = AC²
⇒ 4² + 3² = AC²
⇒16 + 9 = AC²
⇒25 = AC²
⇒√25 = AC (Transferring RHS to LHS by changing sign)
⇒5 = AC
Hence, Zaheer is 5km far from the starting point.
Hope it helps...
