Question

ZB = (205° - 180°) = 25°
2C = (140° - ZB) = (140° -25°) = 115°
and 2A = (65° - 2B) = (65° -25°) = 40°.
Hence, LA = 40°, ZB = 25° and ZC = 115
EXAMPLE 4
SOLUTION
In a AABC, ZA-ZB = 33° and 2B - ZC = 18°. Find the angles of
the triangle
ZA-LB = 33° and ZB-ZC = 18°
ZA= (33° + ZB) and ZC = (ZB-18°).
We know that the sum of the angles of a triangle is 180°.
ZA+ LB + 2C = 180°
(33° + ZB) + 2B +(ZB -18°) = 180° ſusing (1)]
32B = 165° → ZB = 55°.
ZA = (33° + ZB) = (33° +55°) = 88°.
and ZC = (ZB -18°) = (55° - 18°) = 37°.
Hence, ZA = 88°, ZB = 55° and C = 37°.​

Answer 1

Answer:

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Step-by-step explanation:

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