Question

zero).
. A train first travels for 30 min with a velocity
30 km h- and then for 40 min with a velocity
40 km h-1 in the same direction, Calculate : (i) the total
distance travelled, (ii) the average velocity
of the train.
please send this answer ​

Answer 1

30 min =t1

30 km/h=v1

t1=1/2hours

vel=distance/time

30=dis*2

d1=15

case2

v2=40km/h

t2=40min

1hour——60min

xhour------40min

40/60

2/3hours

v2=d2/t2

40=d2/2/3

d2=80/3

1) 15+80/3

45+80/3

125/3km =total d

2) average v

v1+v2/2

70/2

35km/h

Answer 2

i) Total Distance travelled

For first case,

Time = 30 minutes = 1/2 hr

Speed = 30km/hr

Distance = Speed×Time

=30×1/2 = 15km

In second case,

Time = 40minutes = 2/3hr

Speed = 40km/hr

Distance = Speed×Time

= 40×2/3

=26.67km

Total Distance travelled = 15+26.67 = 41.67km ~ 42km approx.

ii) Average Velocity = Displacement/Time

Here, Displacement = Distance

Since, the train travelled in the same direction.

So,

Average Velocity = Distance/ Total Time

= 42 ÷ 7/6

{I have taken the approx value to get a value which is more solvable}

=36km/hr

And

with the exact value of 41.67

the average Velocity will be

= 41.67÷7/6

=41.67 ÷1.16

=35.92km/hr ~ 36km/hr

Cheers!