Let a number be divided into two parts such that one part is 2 less than three times the other part and the number are in the ratio 5:3 . Find the number and its part
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Let the parts be x and y
X=3y-2
X-3y=-2
Given x/y=5/3
3x-5y=0
X-3y=-2
3x-5y=0
3x-9y=-6
-3x+5y=0
-4y=-6
y= 1.5 x=2.5
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Answered by
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Answer:
Let the parts be x and y
X=3y-2
X-3y=-2
Given x/y=5/3
3x-5y=0
X-3y=-2
3x-5y=0
3x-9y=-6
-3x+5y=0
-4y=-6
y= 1.5 x=2.5
Hope it helps you
Please mark me as the brainliest
Step-by-step explanation:
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