Question

Zero of the polynomial (x-3)^2 - (x+3)^2

Answer 1

(x-3)² - (x+3)²

Identity to be used = a² - b² = (a+b)(a-b)

» (x-3+x+3)(x-3-x-3)

» 2x(-6)

» -12x = 0

» x = 0

Answer 2

Answer :

Given :

$: \implies \sf (x\:-\:3)²\:-\:(x\:+\:3)²$

To Find :

$: \implies \sf Zero\:of\:the\:polynomial$

Solution :

$\small{\sf{\red{Identity\:used\::}} \small a²\:-\:b²\:=\:(a\:+\:b)(a\:-\:b)}$

$: \implies \small \sf (x\:-\:3\:+\:x\:+\:3)(x\:-\:3\:-\:x\:-\:3)$

$: \implies \small \sf 2x\:(\:-\:6\:)$

• Now , equate it to Zero .

$: \implies \small \sf 2x\:(\:-\:6\:)\:=\:0$

$: \implies \small \sf 2x\:=\:6$

$: \implies \small \sf x\:=\: \dfrac{6}{2}$

$: \implies \large \sf {\red{x\:=\:3 }}$

• Zero of polynomial is 3 .

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