zeroes of cubic polynomial p(x)=x³-x²are
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Answer:
Given cubic polynomial = x^3 -x^2
Step-by-step explanation:
x^3 -x^2=0
x (x^2 - x) =0
x = 0, (x^2 -x ) = 0
from (x^2 - x) = 0
x (x - 1) = 0
x =0, (x- 1) = 0
from x -1 =0
x = 1
therefore 0 ,0 , 1 are the zeroes of the given polynomial
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