Question

zeroes of poly y2 + 92y +1920

Answer 1

$\blue{\huge{\boxed{\star\: Solution \: \star}}}$


===>
$y {}^{2} + 92y + 1920$


===>
$\red{ \boxed{by \: middle \: term \: splitting}}$


===>
$y {}^{2} + 60y + 32y + 1920$

===>
$\green{ \: taking \: common}$

===> y (y + 60) +32( y +60)

===> ( y + 60) & ( y +32 ) =0

====> y = -60 & y =-32

==>

$\red{ \boxed{ \underline{y = - 60 \: and \: y = - 32}}}$