Zeroes of Quadratic Equation (x-2)(x-3) = 0 are -?
Answers
2,3
reason:
(x-2)=0
x=2
(x-3)=0
x=3
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Answer:Find the zeroes of
y = x4 + x3 – 7x2 – x + 6
First, I'll apply the Rational Roots Test to get a list of possible zeroes. Then I'll find some actual zeroes by testing the possibilities with synthetic division, and finally I'll end up with:
(x + 3)(x – 2)(x + 1)(x – 1) = 0
Solving, I get a list of zeroes: x = ±1, –3, 2
I got these solutions by solving the factors. That's "working frontwards". I can also "work backwards" from the solutions. For instance, for x = 2 to be a solution, then I must have solved the factor equation x – 2 = 0, which means that x – 2 must have been a factor.
The factors we find by working backwards from the zeroes are always of the form "(variable) minus (the given zero)". Having a factor of "(variable) minus (value)" means the same thing as having a solution of "(variable) equals (value)"; that is, if "x – a" is a factor, then "x = a" is a solution, and vice versa. We use this fact to find quadratics from their roots.
Step-by-step explanation: Hope it helped u.