Question

zeroes of the polynomial:

p(x)=x²-1,x=1,-1​

Answer 1

Step-by-step explanation:

p(1)=

${1}^{2} -1$

1-1=0 Hence x=1 is zero of polynomial p (x)

p(-1)=

${ - 1}^{2} - 1$

1-1=0

hence x = -1 is zero of polynomial p(x)