Question

zeroes of x^2-1 . find zeroes​

Answer 1

Answer:1,-1

Step-by-step explanation:

x  ^2 −1=0

⇒x  ^2 −1  ^2 =0

⇒(x−1)(x+1)=0                                                          (∵a  ^2 −b  ^2 =(a−b)(a+b))

⇒(x−1)=0,(x+1)=0

⇒x=1,x=−1

Answer 2

Answer :

Hey buddy !

Here is your answer...

Polynomial :

P(x) = x^2 - 1 = 0 ( given)

= x^2 - (1)^2 = 0

= (x+1) (x-1) = 0

[ Formula used = a^2 - b^2 = (a+b ) (a-b) ]

= ( x+1) =0. (x-1) = 0

= x = -1. x = 1

So, the zeroes are - 1 and 1

Answer...

Thank u☺