Zeros of p(x) = qx - 3 (where q≠0) is
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Answered by
3
Step-by-step explanation:
Given polynomial f(x)=px+q
we know that for zero polynomial f(x)=0
px+q=0
px+q−q=−q
⇒px=−q
x=−pq (because p=0,pq are real number )
Then for value of x is −pq the polynomial is zero polynomial
Answered by
3
f (y) = 0
f (y) = p+ q =0
p = 0-q
p= - q
y = - q/ p
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