Question

zeros of P(x) = x2 -27 are

Answer 1

here AKASHITEMHEAVEN

here is the required answer in the attachment

hope it helps

thanks

Answer 2

Answer :

Hey buddy !

Here is your answer :

P(x) = x^2 - 27

x^2 - 27 = 0

x^2 = 27

x = +-√27

x = +- 3√3

x = + 3√3. x= -3√3

Hope it will be helpful..☺