zinc dissolves in dilute acids to give zn2+.the electrode potential of cell when it is coupled with she and acts as anode,is 0.76v.what is the standard electrode potential of zn2+/zn
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The EMF of the cell is 0.76 volt
ECell = EoAnode + EoCathode
0.76 = EoAnode + 0 or EoAnode = +0.76 V
As the reaction on the anode is oxidation, i.e.,
Zn → Zn2+ + 2e,
EoAnode is the standard oxidation potential of zinc. This potential is given the positive sign.
oox (Zn/Zn2+) = +0.76 volt
So standard reduction potential of Zn, i.e., Eo (Zn/Zn2+)
= Eoox = -(+0.76)
= -0.76 volt
i hope it will help you
regards
ECell = EoAnode + EoCathode
0.76 = EoAnode + 0 or EoAnode = +0.76 V
As the reaction on the anode is oxidation, i.e.,
Zn → Zn2+ + 2e,
EoAnode is the standard oxidation potential of zinc. This potential is given the positive sign.
oox (Zn/Zn2+) = +0.76 volt
So standard reduction potential of Zn, i.e., Eo (Zn/Zn2+)
= Eoox = -(+0.76)
= -0.76 volt
i hope it will help you
regards
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