Chemistry, asked by wathilaedirisinghe28, 19 days ago

Zinc reacts with dilute hydrochloric acid according to the equation:
Zn(s) + 2HCl (aq) → ZnCl2 (aq) + H2 (g)
In the experiment, a 1.046 g sample of an alloy containing zinc reacted with 120.0 mL of 0.200 M HCl solution.
(a) Calculate the amount (in mol) of hydrochloric acid that reacted in the experiment.
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(b) Assuming that the only part of the alloy which reacted with the acid is zinc, calculate the amount of zinc (in mol)
reacting.
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(c) Hence calculate the mass of zinc in the alloy sample.
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Answers

Answered by VaibhavRai22
0

don't know but please mark as brainliest

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