Question

Zinc sulphate reacts with sodium hydroxide first a little then in excess. Write balanced equations for the two reactions with different conditions..
Pls answer ASAP...... ​

Answer 1

Answer:

ZnSO4+2NaOH ->Zn(OH)2+Na2SO4

Zn(OH)2+2NaOH ->Na2ZnO2+2H2O

Answer 2

Answer:

When zinc reacted in limited amount:

Zn+2NaOH→Na₂ZnO₂+H₂↑

(sodium zincate)

When zinc sulphate reacted in limited amount:

ZnSO₄+NaOH→Zn(OH)₂+Na₂SO₄

When reacted in excess:

A perecitate of Zinc Hydroxide is formed

Zn(OH)₂ + 2 OH-(from NaOH)→ Zn(OH)₄-