Question

Zn + 2 HCl —ZnCl2 + H2
How many moles of ZnCl2 will be produced from 61.0 g of Zn, assuming HCl is available in excess?
moles (round to thrqe significant figures)

Answer 1

Answer:

0.938 moles of zinc will be produced. Please mark me as brainliest.

Explanation:

Zinc's mass no. is 65 (approx.)

So, 1 mole of zinc = 65g

61g = 1 mole of zinc x 61/65 = 61/65 moles

So, in 1 mole of ZnCl₂, there will be 1 mole Zn, as all the zinc on the reactants side is in ZnCl₂ on the products side.

But, there is only 61/65 moles of zinc.

So, there is only 61/65 moles of zinc.

= 0.938 moles (to 3 significant digits)