Question

ZN required to form 1.12ml of H2 at stp with hcl is

Answer 1

Equation: [Zn+2HCL---->2nCL2+H2

1mole of Zn produces 1 mole of H2
1mole of Hydrogen gas occupies 22.4litres or [22400ml] at stp
22400ml of hydrogen gas is produced from 1mole of Zn (65g)

22400ml of H2––––>65g
1.12ml of H2 ––––>Zn

=(65*1.12)/22400
=3.25*10^-3
=32.5*10^-4

So, The Zn required to form 1.12ml of H2 ar stp with hcl is 32.5*10^-4