Question

ZO
Example 10. A mass of 200 g of copper having specific
heat capacity 0.095 is heated to 100°C and placed in 100 g of
alcohol at 8°C contained in a copper calorimeter whose mass
is 25 g. The temperature of alcohol rises to 28.5°C. Find the
specific heat capacity of alcohol.​

Answer 1

A mass of 200 g of copper having specific  

heat capacity 0.095 is heated to 100°C and placed in 100 g of  

alcohol at 8°C contained in a copper calorimeter whose mass  

is 25 g. The temperature of alcohol rises to 28.5°C. Find the  

specific heat capacity of alcohol.​

Thanks me

Mark me as brainliest :-)

Answer 2

Answer:

The specific heat capacity of alcohol is $0.64cal/g^oC$.

Explanation:

According to the principle of calorimetry, the amount of heat released by a hot body is equal to the amount of heat absorbed by the cold body.

The amount of heat required to raise the temperature of 1 gram of  substance through 1°C is given by

$Q=ms\Delta T$  

where s is the called specific heat capacity.

Given the mass of copper, $m_1=200 g$

The specific heat capacity of copper, $s_c=0.095cal/g^{o} C$

Temperature of copper, $T_1= 100^{o} C$

The mass of calorimeter, $m_2=25 g$

The mass of alcohol, $m_3=100 g$

Temperature of  alcohol, $T_3= 8^{o} C$

Final temperature of  alcohol, $T_f= 28.5^{o} C$

And the mixture of water from two taps, gives the temperature 30°C

Applying the principle and the formula to the present case, we can write

Heat lost by copper = Heat gained by alcohol and calorimeter

$m_1s_c(T_1-T_f)=m_2s_c(T_f-T_3)+m_3s_a(T_f-T_3)$

$\implies 200\times 0.095(100-28.5)=25\times 0.095(28.5-8)+100\times s_a(28.5-8)$

$\implies 2\times 9.5\times71.5=25\times 0.095\times20.5+100\times s_a\times20.5$

$\implies 1358.5=48.6875+ s_a\times2050$

$\implies s_a=\dfrac{1358.5-48.69}{2050} =\dfrac{1309.81}{2050} =0.64cal/g^oC$

Therefore, the specific heat capacity of alcohol is $0.64cal/g^oC$.

For more problems

brainly.in/question/20029111    

brainly.in/question/13240181