Math, asked by sanjay12475, 11 months ago

zr_hx = ^/ z=(x^) (),​

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Answered by Rockysingh07
0

zr_hx = ^/ z=(x^) (),

(ZR], HX) is the analogue of the Hurewicz map Ti(X) - Hi(X) in ordinary ... As noted above, we have H(S') = Z[1] and H(T) = Z(1)[2] .

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