Question

0.11
The no
The normality of a solution obtained by mixing 100
ml of 0.2 N HChand 500 ml of 0.12 M H,SO, is-
(A) 0.233 N
(B) 0.466 N
(C) 0.116 N
(D) 2.33 N​

Answer 1

Answer:

Explanation:

N=M×n factor

N= 0.12×2= 0.24N

N3V3= N1V1+N2V2

N3= 100×0.2+ 500×0.24/600

N3= 20+125/600

N3= 145/600

N3= 0.241N