Question

0.24 gram of sample of compound of Oxygen and boron was found by analysis to contain 0.096 gram of boron and 0.144 gram of oxygen calculate the percentage composition of the compound by weight​

Answer 1

Hi.

answer

%of composition of boron = 0.096/0.24×100 = 9.6/0.24

So,make them both a whole number by multiplying them by 100

Then, 9.6×100/0.24×100 = 96/24

=40% of boron

Next,

%of oxygen= 0.144/0.24 ×100=14.4×0.24

Make them a whole number by multiplying 100

So,

14.4 ×100/0.24×100= 60

So,60 %of oxygen

11.4x100/0.24×100 = 1440

Answer 2

Answer:

go through the above attachment please