0.3 portion of a pole is in mud, 0.5 portion is in water and the remaining portion is above water.
(a) What portion of the pole is in mud and water in total?
(b) What portion of the pole is above water?
(c) If the portion above water is 2.6 m, what is the length of the pole?
Answers
Step-by-step explanation:
Given :-
0.3 portion of a pole is in mud, 0.5 portion is in water and the remaining portion is above water.
To find :-
(a) What portion of the pole is in mud and water in total?
(b) What portion of the pole is above water?
(c) If the portion above water is 2.6 m, what is the length of the pole?
Solution :-
Let the total length of the pole be X m
The portion of the pole in the mud
= 0.3 of the length of the pole
= 0.3 of X
=> 0.3 X m
The portion of the pole in the water
= 0.5 of the length
= 0.5 of X
= 0.5X m
The length of the pole is in mud and water in total
= 0.3X + 0.5 X
=0.8 X
= 0.8 of the total length of the pole
The portion of the pole is in mud and water in total = 0.8
Remaining length of the pole
=> X - 0.8X
=> X-(8X/10)
=> (10X-8X)/10
=> 2X/10
=> 0.2X m
The length of the pole above the water = 0.2X m
The portion of the pole is above water = 0.2
According to the given problem
The total lenth of the pole above the water level
=2.6 m
=> 0.2X = 2.6
=> X = 2.6/0.2
=> X = (26/10)/(2/10)
=> X = (26/10)×(10/2)
=> X = 26/2
=> X = 13 m
Total length of the pole = 13 m
Answer :-
a) The portion of the pole is in mud and water in total = 0.8
b) The portion of the pole is above water = 0.2
c) the portion above water is 2.6 m, what is the length of the pole = 13 metres