0.48 gram sample of compound of course Oxygen and Boron was found by analysis to contain 0.1 92 gram of Boron and 0.288 gram of oxygen calculate the percentage composition of the compound by weight
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6
Mass of boron as given = 0.096 g
Mass of oxygen as given = 0.144 g
Mass of sample as given = 0.24 g
∴ Percentage of boron by weight in the compound = (0.096 ÷ 0.24 ) x 100 = 40%
∴ Percentage of oxygen by weight in the compound = (0.144 ÷ 0.24) x 100 = 60%
Mass of oxygen as given = 0.144 g
Mass of sample as given = 0.24 g
∴ Percentage of boron by weight in the compound = (0.096 ÷ 0.24 ) x 100 = 40%
∴ Percentage of oxygen by weight in the compound = (0.144 ÷ 0.24) x 100 = 60%
Answered by
0
Answer:
mass of carbon= 0.192g
mass of oxygen= 0.2888g
mass of the sample= 0.48g
percentage composition of carbon= 0.192 divided by 0.48 * 100
0.192 ÷ 0.48 × 100
192/1000 × 100/48 × 100 (removing decimal point and dividing)
1920/48 (by cancelling)
=40%
percentage composition of oxygen= 100% - 40%
=60%
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