Question

0.5 gm of an organic compound in Kjeldhal method produce NH3 , which is completely neutralised by 100 ml of 0.1 N H2SO4 .The percentage of nitrogen in organic compound is​

Answer 1

Mass of organic compound = 0.50 g

Mass of organic compound = 0.50 g60 mL of 0.5 M solution of NaOH is required by residual acid for neutralisation

Mass of organic compound = 0.50 g60 mL of 0.5 M solution of NaOH is required by residual acid for neutralisation ⇒ 60 mL of 0.5 M solution of NaOH =

Mass of organic compound = 0.50 g60 mL of 0.5 M solution of NaOH is required by residual acid for neutralisation ⇒ 60 mL of 0.5 M solution of NaOH = 2

Mass of organic compound = 0.50 g60 mL of 0.5 M solution of NaOH is required by residual acid for neutralisation ⇒ 60 mL of 0.5 M solution of NaOH = 260

Mass of organic compound = 0.50 g60 mL of 0.5 M solution of NaOH is required by residual acid for neutralisation ⇒ 60 mL of 0.5 M solution of NaOH = 260

Mass of organic compound = 0.50 g60 mL of 0.5 M solution of NaOH is required by residual acid for neutralisation ⇒ 60 mL of 0.5 M solution of NaOH = 260 mL of 0.5M H

Mass of organic compound = 0.50 g60 mL of 0.5 M solution of NaOH is required by residual acid for neutralisation ⇒ 60 mL of 0.5 M solution of NaOH = 260 mL of 0.5M H 2

Mass of organic compound = 0.50 g60 mL of 0.5 M solution of NaOH is required by residual acid for neutralisation ⇒ 60 mL of 0.5 M solution of NaOH = 260 mL of 0.5M H 2

Mass of organic compound = 0.50 g60 mL of 0.5 M solution of NaOH is required by residual acid for neutralisation ⇒ 60 mL of 0.5 M solution of NaOH = 260 mL of 0.5M H 2 SS

Since 1000mL of 1M NH

Since 1000mL of 1M NH 3

Since 1000mL of 1M NH 3

Since 1000mL of 1M NH 3 contains 14g of nitrogen,

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH 3

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH 3

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH 3 will contain =

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH 3 will contain = 1000

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH 3 will contain = 100014×40

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH 3 will contain = 100014×40

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH 3 will contain = 100014×40 ×0.5 = 0.28g of N

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH 3 will contain = 100014×40 ×0.5 = 0.28g of NTherefore, percentage of N in 0.50g of organic compound =

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH 3 will contain = 100014×40 ×0.5 = 0.28g of NTherefore, percentage of N in 0.50g of organic compound = 0.50

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH 3 will contain = 100014×40 ×0.5 = 0.28g of NTherefore, percentage of N in 0.50g of organic compound = 0.500.28

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH 3 will contain = 100014×40 ×0.5 = 0.28g of NTherefore, percentage of N in 0.50g of organic compound = 0.500.28

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH 3 will contain = 100014×40 ×0.5 = 0.28g of NTherefore, percentage of N in 0.50g of organic compound = 0.500.28 ×100=56%

Since 1000mL of 1M NH 3 contains 14g of nitrogen,∴ 40mL of 0.5M NH 3 will contain = 100014×40 ×0.5 = 0.28g of NTherefore, percentage of N in 0.50g of organic compound = 0.500.28 ×100=56%Hence, the correct answer is 56%.

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