Math, asked by Nishant0012, 11 months ago

(0.9x+0.7y)(0.81x^2-0.63xy+0.49y^2)​

Answers

Answered by tanusonwan
13

Please tell whether it is correct or not

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shadowsabers03: How did you get this answer?
Answered by shadowsabers03
37

According to a^3+b^3=(a+b)(a^2-ab+b^2) \\ \\,

(0.9x+0.7y)(0.81x^2-0.63xy+0.49y^2) \\ \\ (0.9x+0.7y)((0.9x)^2-(0.9x \times 0.7y)+(0.7y)^2) \\ \\ (0.9x)^3+(0.7y)^3 \\ \\ 0.729x^3+0.343y^3

Hope this helps. ^_^

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